Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 58

Answer

$\{\frac{10}{9}, 2\}$

Work Step by Step

Step 1. Rewrite the equation as $\sqrt {4x+1}=\sqrt {x-1}+2$ Step 2. Take square on both sides to get: $4x+1=x-1+4\sqrt {x-1}+4$ or $3x-2=4\sqrt {x-1}$ Step 3. Take square on both sides again to get: $9x^2-12x+4=16x-16$ or $9x^2-28x+20=0$ which gives $x=\frac{10}{9}, 2$ Step 4. Check answers in the original equation: they both fit.
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