Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 102

Answer

$\{-32,1\}$

Work Step by Step

Step 1. Let $u=(x)^{-1/5}$, we have $2u^2-u-1=0$ Step 2. Factor and solve: $(u-1)(2u+1)=0$ thus $u=-\frac{1}{2}, 1$ Step 3. For $u=-\frac{1}{2}$, we have $(x)^{-1/5}=-\frac{1}{2}$ thus $x=-32$ Step 4. For $u=1$, we have $(x)^{-1/5}=1$ thus $x=1$ Step 5. Solution set $\{-32,1\}$
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