Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 134: 53

Answer

(a) $549.2$ million metric tons (b) $2019$.

Work Step by Step

(a) Given $y=0.0429x^2-9.73x+606$, for $x=2014-2008=6$, we have $y=0.0429(6)^2-9.73(6)+606\approx549.2$ million metric tons (b) let $y=500$, we have $500=0.0429x^2-9.73x+606$ or $0.0429x^2-9.73x+106=0$ which can be solved using the quadratic formula (discard the other bigger number) to get $x\approx11$ which means year $2019$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.