Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 131: 34

Answer

$10.6\ in$

Work Step by Step

Step 1. Use the dimensions given in the exercise, we have the volume as $V=(2.3)(x-3.2)(x)=180.4$ Step 2. Rewrite the above equation as $2.3x^2-7.36x-180.4=0$ Step 3. Let $a=2.3, b=-7.36, c=-180.4$, use the quadratic formula to solve the equation and discard the negative answer to get $x\approx 10.6\ in$
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