Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 130: 24

Answer

the dimensions of the garden is $ 100m$ by $50m$

Work Step by Step

Given: $P=300m$ (based on the enclosed fencing) $A=5000m^{2}$ $L=150-x$ $W=x$ Remember the formula for perimeter and area: $P = 2(L+W)$ $300 = 2(L+W)$ $A = L×W$ $5000 = L×W$ Substitute the given value of L to the area equation $5000 = L×W$ $5000 = (150-W)×W$ Simplify by factoring $5000 = 150W-W{2}$ $W^{2} -150W+5000 = 0 $ $(W-100)(W-50) = 0$ So $W = 100$ or $W = 50$ Since we already found the value of W. Now it's time to solve for L. $L = 150 - W$ if W = 50m $L = 100m$ if W = 100m $L = 50m$ So the dimensions of the garden is $100m$ by $50m$.
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