Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 129: 6

Answer

Option C: $$40=-16t^2+60t$$

Work Step by Step

The formula for the height in feet $s$, of an object launched vertically at 60 feet/sec after $t$ seconds is given as: $s=-16t^2+60t$ To find the time when the object reaches 40ft, plug in $40$ for $s$: $$40=-16t^2+60t$$ Which is option C
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