Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises: 11

Answer

$12,14$

Work Step by Step

Lets call the first integer x, and the second x + 2 $x(x+2) = 110$ $x^2 + 2x = 110$ $x^2 + 2x -110= 0$ $(x-12)(x+14) = 0$ $x = -14, 12$ The correct solution is 12, because -14 is not an integer. Therefore the numbers are $12,14$.
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