Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 129: 10

$10,11$

Lets call the first integer x, and the second x + 1 $x(x+1) = 110$ $x^2 + x = 110$ $x^2 + x -110= 0$ $(x-10)(x+11) = 0$ $x = -11, 10$ The correct solution is 10, because -11 is not an integer. Therefore the numbers are $10,11$.