Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises: 10

Answer

$10,11$

Work Step by Step

Lets call the first integer x, and the second x + 1 $x(x+1) = 110$ $x^2 + x = 110$ $x^2 + x -110= 0$ $(x-10)(x+11) = 0$ $x = -11, 10$ The correct solution is 10, because -11 is not an integer. Therefore the numbers are $10,11$.
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