Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 46: 85

Answer

$2$

Work Step by Step

RECALL: $a^{\frac{1}{3}}=\sqrt[3]{a}.$ Use the rule above to obtain $\sqrt[3]{8} \\=\sqrt[3]{2^3} \\=2.$
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