Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set: 63

Answer

$1$

Work Step by Step

Any number raised to the 0th power is equal to 1. Therefore, $(\frac{3a^{-5}b^2}{12a^3b^{-4}})^0=1$
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