Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 46

Answer

$99x^{17}$

Work Step by Step

Start with given expression: $(11x^{5})(9x^{12})$ Group factors with the same bases: $(11\times9)(x^{5}x^{12})$ Simplify using multiplication rules: $99x^{17}$
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