Answer
$\frac{1}{x^{12}y^{16}z^{20}}$
Work Step by Step
$(\frac{x^{3}y^{4}z^{5}}{x^{-3}y^{-4}z^{-5}})^{-2}=((x^{3}y^{4}z^{5})(x^{3}y^{4}z^{5}))^{-2}=(x^{6}y^{8}z^{10})^{-2}=\frac{1}{(x^{6}y^{8}z^{10})^{2}}=\frac{1}{x^{12}y^{16}z^{20}}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 111
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