Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set - Page 18: 120

Answer

$-10$

Work Step by Step

$\frac{12 \div 3 * 5 |2^2 + 3^2| }{7 + 3 - 6^2}=\frac{12 \div 3 * 5 |4 + 9| }{7 + 3 - 36}=\frac{12 \div 3 * 5 |13| }{-26}=\frac{4*65}{-26}=\frac{260}{-26}=-10$
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