Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set - Page 17: 55

Answer

$5-\sqrt 2$

Work Step by Step

Since $\sqrt 2 - 5$ is negative, we must negate it to find the distance from 0 and, therefore, the absolute value: $-(\sqrt 2 - 5) = 5-\sqrt 2$ . Therefore, $|\sqrt 2 - 5| = 5-\sqrt 2$.
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