Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point: 8

Answer

$\frac{3}{4}$

Work Step by Step

Recall that any number raised to the $0^\text{th}$ power is 1, and that $x^{m/n}=\sqrt[n] {x^m}$. We use these rules and the basic laws of exponents to simplify: $$\left(\frac{2}{7}\right)^0-32^{-2/5}$$$$1-\frac{1}{32^{2/5}}$$$$1-\frac{1}{\sqrt[5] {32^2}}$$ $$1-\frac{1}{4}$$$$\frac{3}{4}$$
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