Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set: 1

Answer

sin θ = $\frac{3}{5}$ cos θ = $\frac{4}{5}$ tan θ =$\frac{3}{4}$ csc θ = $\frac{5}{3}$ sec θ = $\frac{5}{4}$ cot θ = $\frac{4}{3}$

Work Step by Step

$a^{2}$ + $b^{2}$ = $c^{2}$ given a = 9, b= 12 $9^{2}$ + $12^{2}$ = $c^{2}$ $c^{2}$ = 81 + 144 $c^{2}$ = 225 c = $\sqrt {225}$ = 15 sin θ = $\frac{opposite}{hypotenuse}$ = $\frac{9}{15}$ sin θ = $\frac{3}{5}$ cos θ = $\frac{adjacent}{hypotenuse}$ = $\frac{12}{15}$ cos θ = $\frac{4}{5}$ tan θ = $\frac{opposite}{adjacent}$ = $\frac{9}{12}$ tan θ = $\frac{3}{4}$ csc θ = $\frac{1}{sin θ}$ = $\frac{5}{3}$ sec θ = $\frac{1}{cos θ}$ = $\frac{5}{4}$ cot θ = $\frac{1}{tan θ}$ = $\frac{4}{3}$
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