Answer
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Work Step by Step
The range of the sine function is within $[-1,1]$. In a unit circle $x^2+y^2=1$, we have $sin(t)=y$ and since $y\in[-1,1]$, we have $sin(t)\in[-1,1]$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 549: 88
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