Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 489: 98

Answer

Solution set = $\{ -\sqrt{\frac{\ln 50}{\ln 5}},\ \sqrt{\frac{\ln 50}{\ln 5}} \}$

Work Step by Step

$5^{x^{2}}=50$ The RHS is not a power of 3. Apply $\ln $(...) $\ln 5^{x^{2}}=\ln 50 ... \quad $ apply power rule $ x^{2}\ln 5=\ln 50$ $ x^{2}=\displaystyle \frac{\ln 50}{\ln 5}$ $ x=\pm\sqrt{\frac{\ln 50}{\ln 5}}$ Solution set = $\{ -\sqrt{\frac{\ln 50}{\ln 5}},\ \sqrt{\frac{\ln 50}{\ln 5}} \}$
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