Answer
$x=7.75$
Work Step by Step
RECALL:
$\log_b{x}=y \longrightarrow b^y=x$
Write the equation in exponential form using the rule above to obtain:
$2^{5}=4x+1
\\32=4x+1$
Solve for $x$ to obtain:
$\begin{array}{ccc}
&32-1&= &4x+1-1
\\&31&=&4x
\\&\frac{31}{4} &= &x
\\&x &=&7.75\end{array}$
