Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Concept and Vocabulary Check - Page 488: 11

Answer

True.

Work Step by Step

Logarithms are defined for positive arguments only. Even though $-10$ is negative, the argument of the logarithm on the RHS equals 25 when $ x=-10$, so the logarithm is defined. Furthermore, $\log_{5}25=\log_{5}(5^{2})=2$, so the statement is true.
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