Answer
False.
Work Step by Step
Logarithms are defined for positive arguments only.
Substituting $-3$ for $ x $ on the RHS, the logarithm $\log_{5}(-3)$ is undefined, so $-3 $ can't be a solution.
False.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Concept and Vocabulary Check - Page 488: 10
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