Answer
$x$
Work Step by Step
RECALL:
$\log_b{x} = y \longrightarrow b^y = x.$
Let $y = \log_b{b^x}.$
Use the rule above to obtain
$b^y=b^x.$
Use the rule "If $a^x=a^y$, then $x=y$" to obtain
$b^y=b^x
\\y=x.$
Therefore,
$\log_b{b^x} = x.$
