Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.7 - Polynomial and Rational Inequalities - Exercise Set - Page 413: 60

Answer

$[-4,2)$

Work Step by Step

Step 1. Rewrite the inequality as $\frac{x}{x+2}-2\geq0$ which gives $\frac{x-2x-4}{x+2}\geq0$, $\frac{-x-4}{x+2}\geq0$, and $\frac{x+4}{x+2}\leq0$ Thus the boundary points are $x=-4,-2$ Step 2. Using test points to examine signs across the boundary points, we have $...(+)...(-4)...(-)...(-2)...(+)...$ Thus the solutions are $-4\leq x\lt-2$ Step 3. We can express the solutions on a real number line as shown in the figure. Step 4. We can express the solutions in interval notation as $[-4,2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.