Answer
-4,5,-6,7
Work Step by Step
To find the first four terms of the sequence whose general term is $a_{n}$ = $(-1)^{n}$(n+3), we replace n in the formula with 1,2,3, and 4.
n=1, $a_{1}$ = $(-1)^{1}$(1+3) = -1 * 4 =-4
n=2, $a_{2}$ = $(-1)^{2}$(2+3) = 1* 5=5
n=3, $a_{3}$ = $(-1)^{3}$(3+3) = -1 *6 = -6
n=4,$a_{4}$ = $(-1)^{4}$(4+3) = 1 *7 = 7
The first four terms are -4,5,-6,7.
