Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Concept and Vocabulary Check - Page 279: 6

Answer

$4$; $16$

Work Step by Step

Completing the square for the $x$ group can be done by adding the square of one-half of the middle term (x-term). Thus, $(\frac{4}{2})^2=4$ will be added to both sides of the equation. Completing the square for the $y$ group can be done by adding the square of one-half of the middle term (y-term). Thus, $(\frac{-8}{2})^2=(-4)^2=16$ will be added to both sides of the equation. Therefore, the missing expressions in the given statements are: $4$ and $16$, respectively.
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