Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.7 - Combinations of Functions; Composite Functions - Concept and Vocabulary Check: 5

Answer

$f(x) \cdot g(x)$

Work Step by Step

RECALL: $(fg)(x) = f(x) \cdot g(x)$. Thus, the missing expression in the given statement is $f(x) \cdot g(x)$.
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