Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Concept and Vocabulary Check - Page 212: 7

Answer

$y-y_1=m(x-x_1)$

Work Step by Step

RECALL: The point-slope form of a line's equation is: $y-y_1=m(x-x_1)$ where m = slope and $(x_1, y_1)$ is a point on the line. Thus, the missing expression in the given statement is: $y-y_1=m(x-x_1)$
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