Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 176: 32

Answer

a) 25 b) -5 c) $-x^3+x+1$ d) $27{{a}^{3}}-3a+1$

Work Step by Step

a) Putting the value of $x=3$ in the equation as follows: $\begin{align} & h\left( 3 \right)={{3}^{3}}-3+1 \\ & =27-3+1 \\ & =25 \end{align}$ b) Putting the value of $x=-2$ in the equation as follows: $\begin{align} & h\left( -2 \right)={{\left( -2 \right)}^{3}}-\left( -2 \right)+1 \\ & =-8+2+1 \\ & =-5 \end{align}$ c) Putting the value of $x=-x$ in the equation as follows: $\begin{align} & h\left( -x \right)={{\left( -x \right)}^{3}}-\left( -x \right)+1 \\ & =-{{x}^{3}}+x+1 \end{align}$ d) Putting the value of $x=3a$ in the equation as follows: $\begin{align} & h\left( 3a \right)={{\left( 3a \right)}^{3}}-\left( 3a \right)+1 \\ & =27{{a}^{3}}-3a+1 \end{align}$
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