Answer
a) 13
b) 1
c) $x^4-x^2+1$
d) $81{{a}^{4}}-9{{a}^{2}}+1$
Work Step by Step
a)
Putting the value of $x=2$ in the equation gives:
$\begin{align}
& h\left( 2 \right)={{2}^{4}}-{{2}^{2}}+1 \\
& =16-4+1 \\
& =13
\end{align}$
b)
Putting the value of $x=-1$ in the equation gives:
$\begin{align}
& h\left( -1 \right)={{\left( -1 \right)}^{4}}-{{\left( -1 \right)}^{2}}+1 \\
& =1-1+1 \\
& =1
\end{align}$
c)
Putting the value of $x=-x$ in the equation gives:
$\begin{align}
& h\left( -x \right)={{\left( -x \right)}^{4}}-{{\left( -x \right)}^{2}}+1 \\
& ={{x}^{4}}-{{x}^{2}}+1
\end{align}$
d)
Putting the value of $x=3a$ in the equation gives:
$\begin{align}
& h\left( 3a \right)={{\left( 3a \right)}^{4}}-{{\left( 3a \right)}^{2}}+1 \\
& =81{{a}^{4}}-9{{a}^{2}}+1
\end{align}$
