Answer
$-a$
Work Step by Step
We know that $\log_a {x}-\log_a {y}=\log_a {\left(\frac{x}{y}\right)}$.
Hence,,
$\ln {0.5}=\ln{\frac{1}{2}}=\ln{1}-\ln{2}$
Note that $\ln {1}=0$.
Thus,
$\ln{1}-\ln{2}
\\=0-\ln{2}
\\=0-a
\\=-a$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 32
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