Answer
(a)
Work Step by Step
Using the known information $H(x)=f\circ g=f(g(x))=\sqrt {25-4x^2}$. Test each choice and we can find (a) is the answer because for (a), we have $f(g(x))=\sqrt {25-(4x)^2}=\sqrt {25-16x^2}\ne H(x)$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 254: 7
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