Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.7 - Temperature and Conversions Between the U.S. and Metric Systems - Exercise Set - Page 680: 71

Answer

$80.6^\circ F$

Work Step by Step

The formula is: $F=C\times\frac{9}{5}+32$ where F is the Fahrenheit and C is Celsius. Here: $F=27\times\frac{9}{5}+32=\frac{243}{5}+32=48.6+32=80.6^\circ F$
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