## Prealgebra (7th Edition)

$T=25$ square cm.
The area of this figure can be calculated as the sum of the rectangle and the triangle on the top. $T=T_1+T_2$ Rectangle: $T_1=a\times b$ $T_17\times 3=21$ square cm. Triangle: $h\times \frac{a}{2}=2\times \frac{7-2\times1\frac{1}{2}}{2}=7-3=4$ square cm $T=T_1+T_2=21+4=25$ square cm.