Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 8 - Test - Page 599: 30

Answer

See attached graph.

Work Step by Step

To find these points on the graph, plug in certain values of x to solve for y: 3x - 2y = 12, where x = 0 3(0) - 2y = 12 0 - 2y = 12 -2y = 12 (-2y) $\div$ -2 = 12 $\div$ -2 y = -6 (0, -6) is the first coordinate. 3x - 2y = 12, where x = 4 3(4) - 2y = 12 12 - 2y = 12 12 - 12 - 2y = 12 -12 2y = 0 y = 0 (4,0) is the second coordinate. 3x - 2y = 12, where x = 1 3(1) - 2y = 12 3 - 2y = 12 3 - 3 - 2y = 12 -3 -2y = 9 -2y $\div$ -2 = 9 $\div$ -2 y = -4.5 (1, -4.5) is the third coordinate.
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