Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 8 - Cumulative Review - Page 600: 7

Answer

$x=2$

Work Step by Step

$\frac{x}{6}+1=\frac{4}{3}$ $\frac{x}{6}+1-1=\frac{4}{3}-1$ $\frac{x}{6}=\frac{1}{3}$ $\frac{x}{6}\times6=\frac{1}{3}\times6$ $x=\frac{6}{3}=2$
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