Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 7 - Section 7.4 - Applications of Percent - Exercise Set - Page 507: 67

Answer

$\frac{28}{39}$

Work Step by Step

2$\frac{4}{5}$ $\div$ 3$\frac{9}{10}$ =$\frac{14}{5}$ $\div$ $\frac{39}{10}$ =$\frac{14}{5}$ $\times$$\frac{10}{39}$ =$\frac{14\times10}{5\times39}$ =$\frac{14\times5\times2}{5\times39}$ =$\frac{14\times2}{39}$ =$\frac{28}{39}$
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