Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 7 - Section 7.4 - Applications of Percent - Exercise Set: 67

Answer

$\frac{28}{39}$

Work Step by Step

2$\frac{4}{5}$ $\div$ 3$\frac{9}{10}$ =$\frac{14}{5}$ $\div$ $\frac{39}{10}$ =$\frac{14}{5}$ $\times$$\frac{10}{39}$ =$\frac{14\times10}{5\times39}$ =$\frac{14\times5\times2}{5\times39}$ =$\frac{14\times2}{39}$ =$\frac{28}{39}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.