Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 428: 77

Answer

$\frac{15}{9}$ =$\frac{5}{3}$ and $\frac{9}{3}$ =$\frac{15}{5}$

Work Step by Step

$\frac{9}{15}$ =$\frac{3}{5}$ Other true proportions are $\frac{15}{9}$ =$\frac{5}{3}$ and $\frac{9}{3}$ =$\frac{15}{5}$
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