Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.1 - Ratios and Rates - Exercise Set - Page 417: 28

Answer

$\frac{2}{7}$

Work Step by Step

3$\frac{1}{2}$ to 5$\frac{1}{4}$ 3$\frac{1}{2}$ $\div$ 5$\frac{1}{4}$ =$\frac{3\times2+1}{2}$ $\div$ $\frac{5\times4+1}{4}$ =$\frac{6+1}{2}$ $\div$ $\frac{20+1}{4}$ =$\frac{7}{2}$ $\div$ $\frac{21}{4}$ =$\frac{7}{2}$ $\times$ $\frac{4}{21}$ =$\frac{7\times4}{2\times21}$ =$\frac{7\times2\times2}{2\times3\times7}$ = $\frac{2}{7}$
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