Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Review - Page 462: 72

Answer

$\frac{4}{9}$

Work Step by Step

$\sqrt {16}=4$ $\sqrt {81}=9$ so $\sqrt {\frac{16}{81}}=\frac{4}{9}$
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