Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Review: 24

Answer

$x=1\frac{1}{8}$

Work Step by Step

Use cross multiplication to solve for x. $\frac{x}{4\frac{1}{2}}=\frac{2\frac{1}{10}}{8\frac{2}{5}}$ $8\frac{2}{5}(x)=({2\frac{1}{10}})(4\frac{1}{2})$ $\frac{42}{5}(x)=({\frac{21}{10}})(\frac{9}{2})$ $\frac{42}{5}(x)\times\frac{5}{42}=\frac{189}{20}\times\frac{5}{42}$ $x=\frac{\big/\!\!\!3\times9\times\big/\!\!\!7\times\big/\!\!\!5}{4\times\big/\!\!\!5\times\big/\!\!\!3\times2\times\big/\!\!\!7}=\frac{9}{8}=1\frac{1}{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.