Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Cumulative Review - Page 466: 26

Answer

$\frac{16}{27}$

Work Step by Step

To find the average, sum the items and divide by the count of items. To add, convert to fractions with least common denominator. $(\frac{3}{5}+\frac{4}{9}+\frac{11}{15})\div3$ =$(\frac{3\times9}{5\times9}+\frac{4\times5}{9\times5}+\frac{11\times3}{15\times3})\div3$ =$(\frac{27}{45}+\frac{20}{45}+\frac{33}{45})\div3$ =$\frac{80}{45}\times\frac{1}{3}$ =$\frac{\big/\!\!\!5\times16}{\big/\!\!\!5\times9\times3}$ =$\frac{16}{27}$
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