Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Cumulative Review - Page 465: 20

Answer

they are equivalent

Work Step by Step

$\frac{10}{55}\overset?=\frac{6}{33}$ $\frac{10\times3}{55\times3}\overset?=\frac{6\times5}{33\times5}$ $\frac{30}{165}\overset?=\frac{30}{165}$
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