Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Cumulative Review: 14

Answer

$15\frac{3}{8}$

Work Step by Step

$3\frac{3}{8}\times4\frac{5}{9}$ $\longrightarrow$ convert to improper fractions =$(\frac{24}{8}+\frac{3}{8})\times(\frac{36}{9}+\frac{5}{9})$ =$\frac{27}{8}\times\frac{41}{9}$ $\longrightarrow$ multiply numerators and denominators =$\frac{27\times41}{8\times9}$ $\longrightarrow$ factor =$\frac{3\times9\times41}{8\times9}$ $\longrightarrow$ eliminate common factors =$\frac{3\times\big/\!\!9\times41}{8\times\big/\!\!9}$ $\longrightarrow$ simplify =$\frac{123}{8}$ $\longrightarrow$ convert to mixed number =$15\frac{3}{8}$
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