Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 5 - Section 5.2 - Adding and Subtracting Decimals - Review - Page 352: 101

Answer

$\frac{4}{9}$

Work Step by Step

$(\frac{2}{3})^2=\frac{2}{3}\times\frac{2}{3}=\frac{4}{9}$
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