Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set: 58

Answer

The solution is -6

Work Step by Step

-$\frac{3}{4}$x = $\frac{9}{2}$ LCD of 4and 2is 4.Multiply by 4both sides 4$\times$-$\frac{3}{4}$x = 4$\times$$\frac{9}{2}$ $\frac{4\times -3x}{4}$=$\frac{4\times9}{2}$ -3x=2$\times$9 -3x=18 Multiply by $\frac{1}{3}$ both sides $\frac{1}{3}$$\times$-3x=$\frac{1}{3}$$\times$18 -x=6 x=-6 The solution is -6 Check Replace x with -6 -$\frac{3}{4}$x = $\frac{9}{2}$ -$\frac{3}{4}$ $\times$-6= $\frac{9}{2}$ $\frac{3\times6}{4}$ = $\frac{9}{2}$ $\frac{3\times2\times3}{2\times2}$ = $\frac{9}{2}$ $\frac{9}{2}$ =$\frac{9}{2}$
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