Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set: 57

Answer

The solution is -$\frac{3}{7}$

Work Step by Step

$\frac{5}{7}$y = -$\frac{15}{49}$ LCD of 7 and 49 is 49.Multiply by 49both sides 49$\times$$\frac{5}{7}$y = 49$\times$-$\frac{15}{49}$ $\frac{49\times5y}{7}$=$\frac{49\times-15}{49}$ 7$\times$5y=-15 35y=-15 Multiply by $\frac{1}{35}$ both sides $\frac{1}{35}$$\times$35y=$\frac{1}{35}$$\times$-15 y=$\frac{5\times-3}{5\times7}$ y=$\frac{-3}{7}$ The solution is $\frac{-3}{7}$ Check Replace y with $\frac{-3}{7}$ $\frac{5}{7}$y = -$\frac{15}{49}$ $\frac{5}{7}$$\times$ -$\frac{3}{7}$= -$\frac{15}{49}$ -$\frac{15}{49}$ = -$\frac{15}{49}$
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