## Prealgebra (7th Edition)

$\frac{x}{4}$ +1 =$\frac{1}{4}$ Subtract 1 from both sides $\frac{x}{4}$ +1-1=$\frac{1}{4}$-1 $\frac{x}{4}$ =$\frac{1}{4}$-$\frac{4}{4}$ $\frac{x}{4}$ =-$\frac{3}{4}$ Multiply by 4 both sides 4$\times$$\frac{x}{4}$ =4$\times$-$\frac{3}{4}$ x=-3 The solution is -3 Check Replace x with -3 $\frac{x}{4}$ +1 =$\frac{1}{4}$ $\frac{-3}{4}$ +1 =$\frac{1}{4}$ $\frac{-3}{4}$ +$\frac{4}{4}$ = $\frac{1}{4}$ $\frac{1}{4}$ =$\frac{1}{4}$