## Prealgebra (7th Edition)

The solution is -$\frac{7}{8}$
$\frac{1}{2}$ + a= -$\frac{3}{8}$ $\frac{1}{2}$+a -$\frac{1}{2}$=- $\frac{3}{8}$-$\frac{1}{2}$ Subtract $\frac{1}{2}$ to both sides $a=-\frac{3}{8}$-$\frac{4}{8}$ LCD of the denominators 8 and 2 is 8 $a=-\frac{3}{8}$-$\frac{4}{8}$ $a=\frac{-3-4}{8}$ $a= -\frac{7}{8}$ The solution is -$\frac{7}{8}$ Check Replace y with $\frac{-7}{8}$ $\frac{1}{2}$ +a=-$\frac{3}{8}$ $\frac{1}{2}$ -$\frac{7}{10}$=-$\frac{3}{10}$ $\frac{1}{2}$ -$\frac{7}{8}$=-$\frac{3}{8}$ $\frac{4}{8}$-$\frac{7}{8}$=-$\frac{3}{8}$ $\frac{4-7}{8}$=-$\frac{3}{8}$ -$\frac{3}{8}$=-$\frac{3}{8}$