Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 9

Answer

$\frac{2x}{13}$

Work Step by Step

$\frac{\frac{3x}{4}}{5-\frac{1}{8}}$ $=(\frac{3x}{4})\div({5-\frac{1}{8}})$ $=(\frac{3x}{4})\div({\frac{40}{8}-\frac{1}{8}})$ $=\frac{3x}{4}\div{\frac{39}{8}}$ $=\frac{3x}{4}\times{\frac{8}{39}}$ $=\frac{x}{1}\times{\frac{2}{13}}$ $=\frac{2x}{13}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.