Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Practice - Page 268: 5

Answer

$\frac{5}{24}$

Work Step by Step

$\frac{5}{8}-\frac{1}{3}-\frac{1}{12}$ $=\frac{5\times3}{8\times3}-\frac{1\times8}{3\times8}-\frac{1\times2}{12\times2}$ $=\frac{15}{24}-\frac{8}{24}-\frac{2}{24}$ $=\frac{7}{24}-\frac{2}{24}$ $=\frac{5}{24}$
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